12-12-2010, 11:10 PM | #91 | |
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12-13-2010, 01:21 AM | #92 |
It's Dr. Penguin now!
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Ok, here's my scientific answer: midday, slightly below midway, and I know because the monk calls me on his droid x and says "Hey, Grace, so I just passed the point I was at exactly at this time a few days ago! cool, eh? I know because I left my Bible here because it was getting too heavy to carry up and I have the passages memorized anyway. Don't forget to bring my other brown cloak and a bell when you pick me up tonight!"
And if I don't answer, he'll swype it to me, and probably get a few words wrong, so I may bring Nell instead, and perhaps some brown coal instead. |
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12-13-2010, 01:44 AM | #93 |
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Gracie, I think that you are the winner. Hopefully TGS will get out of bed and confirm it. Cheers
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12-13-2010, 04:27 AM | #94 |
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Ah, the question was, can you prove that there is a place where the monk is at the same time of day on the way up as on the way down - not to say what that place is. Now, there are mathematical solutions to the problem involving Brouwer's Fixed Point Theorem, which are virtually useless for actually understanding the solution. Much better is to use your intuition - imagine that a monk starts from the bottom of the mountain at sunrise, and another monk starts from the top of the mountain at sunrise. Now you can simply "see" that these two monks will pass each other and, hence, be at the same place on the path at the same time - though you don't know where or when, (but that's not what you are asked). From this you can also simply "see" that if the journeys take place on different days this makes no difference to whether the monks pass the same place at the same time of day.
Hope that helps. Apparently Arthur Koestler is responsible for this puzzle. |
12-13-2010, 05:01 AM | #95 |
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My answer is no. I can not prove it, he could have dematerialized at some stage.
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12-13-2010, 05:31 PM | #96 |
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I can only prove it with my imagination. Or a mathematical equation. Or a diagram. All require spatial concepts that a mere snake cannot understand.
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12-13-2010, 06:27 PM | #97 | |
Now what?
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12-14-2010, 05:13 AM | #98 |
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12-14-2010, 05:31 PM | #99 |
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neither! because you have used capitals in your answer choices and a lowercase a in your question! Hee hee My turn!
Which of these numbers does not belong in the following list? :... 1, 4, 7, 9, 11, 14. |
12-15-2010, 01:43 AM | #100 |
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14 does not belong. All the others have only have only one unique divisor (not including the identity).
1x1=1 2x2=4 7*1=7 3*3=9 11*1=1 7*2=14 X |
12-15-2010, 04:05 AM | #101 |
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12-15-2010, 04:06 AM | #102 |
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To fix you up. How about I ask it again.
only the list = 1, 4, 7, 9, 11, 17. |
12-15-2010, 04:07 AM | #103 |
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9? (is too short a post apparently)
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12-15-2010, 04:08 AM | #104 |
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12-15-2010, 04:10 AM | #105 |
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Intuitively, with no workings out, it might have something to do with the addition of 3?
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